## Linear Operators: Spectral theory |

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Page 1297

The first

Now Ti(t) is an adjoint (Theorem 10); therefore (cf. XII.1.6) £(T(r)) is complete in

the

of ...

The first

**norm**is the**norm**of the pair [f, Tif) as an element of the graph of Ti(t).Now Ti(t) is an adjoint (Theorem 10); therefore (cf. XII.1.6) £(T(r)) is complete in

the

**norm**||f||1. Since the two additional terms in f2 are the**norm**of f as an elementof ...

Page 1431

Leto, and 3), be the closures of £(To(t')) in the

respectively. By step (c) we have that Q, Doi. Let ge og, and let {gn} be a Cauchy

sequence in Q(To(t')) which converges to g in the

is in ...

Leto, and 3), be the closures of £(To(t')) in the

**norms**of Q(Ti(r')) and £(Ti(t))respectively. By step (c) we have that Q, Doi. Let ge og, and let {gn} be a Cauchy

sequence in Q(To(t')) which converges to g in the

**norm**of £(Ti(t)). To show that gis in ...

Page 1639

Then for a function f in one of the spaces C*(I), C*(I), or C.(I), we place a(f; J, m) =

sup|6"f(r), are Kn and define the

. m) . *To so so. 2"2"j! 1+u(f; J, m) This

Then for a function f in one of the spaces C*(I), C*(I), or C.(I), we place a(f; J, m) =

sup|6"f(r), are Kn and define the

**norm**of f by the equation co k - |f| = X X o * - u(f, J. m) . *To so so. 2"2"j! 1+u(f; J, m) This

**norm**makes each of the spaces listed ...### What people are saying - Write a review

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### Contents

BAlgebras | 859 |

Bounded Normal Operators in Hilbert Space | 887 |

Spectral Representation | 909 |

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