Linear Operators: Spectral operators |
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Page 2144
It clearly preserves finite disjoint unions , takes complements into complements ,
is countably additive in the X topology of X * , and is bounded . It remains only to
show that A ( 0 ) A ( 8 ) = A ( od ) . It is seen , by using the above remarks , that for
...
It clearly preserves finite disjoint unions , takes complements into complements ,
is countably additive in the X topology of X * , and is bounded . It remains only to
show that A ( 0 ) A ( 8 ) = A ( od ) . It is seen , by using the above remarks , that for
...
Page 2203
The mapping E HO ( E ) is clearly an isomorphism between B and the Boolean
algebra of all open and closed subsets of 1 . These open and closed sets o ( E )
form a basis for the topology in 1 . To see this , note that sets of the form { a | | ( T ...
The mapping E HO ( E ) is clearly an isomorphism between B and the Boolean
algebra of all open and closed subsets of 1 . These open and closed sets o ( E )
form a basis for the topology in 1 . To see this , note that sets of the form { a | | ( T ...
Page 2319
Then , if f is in the domain D ( T ) , the series expansion ; T ) f converges to f
unconditionally in the topology of A ( n ) ( J ) . PROOF . The series 1 E ( Ni ; T ) f
certainly converges unconditionally in the topology of L2 ( J ) . On the other hand
, so ...
Then , if f is in the domain D ( T ) , the series expansion ; T ) f converges to f
unconditionally in the topology of A ( n ) ( J ) . PROOF . The series 1 E ( Ni ; T ) f
certainly converges unconditionally in the topology of L2 ( J ) . On the other hand
, so ...
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