Linear Operators: Spectral operators |
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Page 2044
On the real axis 0 = 0 and hence , since T ( t ) is strongly continuous at t = 0 , ( 82
) T ( t ) l SK , Ost < 00 , a fact which also follows from ( 61 ) . The inequality ( 81 )
shows that T ( 5 ) is strongly continuous at $ = 0 provided remains in a sector - 4 ...
On the real axis 0 = 0 and hence , since T ( t ) is strongly continuous at t = 0 , ( 82
) T ( t ) l SK , Ost < 00 , a fact which also follows from ( 61 ) . The inequality ( 81 )
shows that T ( 5 ) is strongly continuous at $ = 0 provided remains in a sector - 4 ...
Page 2194
Strongly Closed Algebras and Complete Boolean Algebras In this section an
attempt will be made to characterize the strong closure of a commutative algebra
of spectral operators . It has been observed ( cf . VI . 1 . 5 ) that a convex set in the
...
Strongly Closed Algebras and Complete Boolean Algebras In this section an
attempt will be made to characterize the strong closure of a commutative algebra
of spectral operators . It has been observed ( cf . VI . 1 . 5 ) that a convex set in the
...
Page 2220
... Tư ) → R ( 1 ; T ) strongly . Now let r be an element of the class R ( V ) of
rational functions which are continuous on V . Then r ( Ta ) is a finite product of
terms of the form XI – Tą and R ( 2 ; T . ) . Thus , since the product of bounded ,
strongly ...
... Tư ) → R ( 1 ; T ) strongly . Now let r be an element of the class R ( V ) of
rational functions which are continuous on V . Then r ( Ta ) is a finite product of
terms of the form XI – Tą and R ( 2 ; T . ) . Thus , since the product of bounded ,
strongly ...
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