Linear Operators: Spectral operators |
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Page 2025
Since Ex : ( s ) # 0 there is a vector f ( s ) in EP with \ ¥ ( s ) = 1 and ( s ) = Êxj ( s ) (
s ) . Thus , since Êx ; ( s ) and Êxg ( s ) are disjoint projections if q # j , it follows
from ( 35 ) that R ( a ; Â ( s ) ) " } ( s ) = 4 ( s ) ( 1 - dxy ( s ) ) - - and ( 39 ) gives -
Axy ...
Since Ex : ( s ) # 0 there is a vector f ( s ) in EP with \ ¥ ( s ) = 1 and ( s ) = Êxj ( s ) (
s ) . Thus , since Êx ; ( s ) and Êxg ( s ) are disjoint projections if q # j , it follows
from ( 35 ) that R ( a ; Â ( s ) ) " } ( s ) = 4 ( s ) ( 1 - dxy ( s ) ) - - and ( 39 ) gives -
Axy ...
Page 2031
To prove ( iv ) suppose first that ys is in 0 in which case a permissible interchange
of integration gives RN RN ( FT . ) q ) = S ( Fp ) ( $ ) { ( 8 ) ds = S 968 ) ( F % ) ( 3 )
ds = Trulm ) , de D . Now 0 is dense in H = L2 ( RN ) and thus there is for an ...
To prove ( iv ) suppose first that ys is in 0 in which case a permissible interchange
of integration gives RN RN ( FT . ) q ) = S ( Fp ) ( $ ) { ( 8 ) ds = S 968 ) ( F % ) ( 3 )
ds = Trulm ) , de D . Now 0 is dense in H = L2 ( RN ) and thus there is for an ...
Page 2065
Thus the Gelfand theory gives a general procedure for determining whether or
not an element possesses an inverse and so ... In order to apply this procedure to
a given algebra , it is sufficient to give a satisfactory representation of its spectrum
...
Thus the Gelfand theory gives a general procedure for determining whether or
not an element possesses an inverse and so ... In order to apply this procedure to
a given algebra , it is sufficient to give a satisfactory representation of its spectrum
...
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