Linear Operators: Spectral operators |
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Page 2149
If the resolvent set is dense , then any two analytic , or even continuous ,
extensions of R ( A ; T ' ) x must coincide on their common domain of continuity .
Q . E . D . All of the special type operators to be considered in the present section
will ...
If the resolvent set is dense , then any two analytic , or even continuous ,
extensions of R ( A ; T ' ) x must coincide on their common domain of continuity .
Q . E . D . All of the special type operators to be considered in the present section
will ...
Page 2156
are both dense in X . Since M , is dense in X , the manifold ( 141 – T ' ) NM2 + { x |
( 1 , 1 – T ) ^ x = 0 } is dense in X , so that ( 141 – T ' ) N ( 12I – T ' ) NX + { x | ( 1 , 1
– T ) Nx = 0 } + { x | ( 12I – T ) ^ x = 0 } is also dense in X . By Lemma 7 , o ( x ) ...
are both dense in X . Since M , is dense in X , the manifold ( 141 – T ' ) NM2 + { x |
( 1 , 1 – T ) ^ x = 0 } is dense in X , so that ( 141 – T ' ) N ( 12I – T ' ) NX + { x | ( 1 , 1
– T ) Nx = 0 } + { x | ( 12I – T ) ^ x = 0 } is also dense in X . By Lemma 7 , o ( x ) ...
Page 2159
The union of all intervals of constancy relative to T is an open set dense in To .
PROOF . It is clear that the union of intervals of constancy is open . To see that it
is dense , let y be a closed subarc of T ' , having positive length and let Yn = { 10
10 ...
The union of all intervals of constancy relative to T is an open set dense in To .
PROOF . It is clear that the union of intervals of constancy is open . To see that it
is dense , let y be a closed subarc of T ' , having positive length and let Yn = { 10
10 ...
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