Linear Operators: Spectral operators |
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Page 1934
Proof . Using Theorem 2 , we see that if o ( x ) is void , then x ( $ ) is everywhere
defined , single valued , and hence entire . Since , by VII . 3 . 4 , lim x * x ( f ) = lim
x * R ( É ; T ' ) x = 0 , $ 20 $ + 00 it is seen that x * x ( 5 ) = 0 for all & and all 3 * € X
...
Proof . Using Theorem 2 , we see that if o ( x ) is void , then x ( $ ) is everywhere
defined , single valued , and hence entire . Since , by VII . 3 . 4 , lim x * x ( f ) = lim
x * R ( É ; T ' ) x = 0 , $ 20 $ + 00 it is seen that x * x ( 5 ) = 0 for all & and all 3 * € X
...
Page 2093
It is readily seen that X ( F ) is a linear manifold in X , but it need not be closed
even when F is closed ; an elementary counterexample is given in Colojoară and
Foiaş [ 4 ; p . 25 ] . If T is a spectral operator with resolution of the identity E and if
8 ...
It is readily seen that X ( F ) is a linear manifold in X , but it need not be closed
even when F is closed ; an elementary counterexample is given in Colojoară and
Foiaş [ 4 ; p . 25 ] . If T is a spectral operator with resolution of the identity E and if
8 ...
Page 2163
8 , it is seen that , for some constant K , FLEJE ( ) – Ë FLEJE / 0 ) | = È Ž { F ( E . ) –
F { E } E ( 0 , 01 ) SK sup F ( $ i ) – F ( $ i ) ) , where the supremum is taken over
those i and j for which 0 , 0 , is not void . If by the norm 71 is understood the ...
8 , it is seen that , for some constant K , FLEJE ( ) – Ë FLEJE / 0 ) | = È Ž { F ( E . ) –
F { E } E ( 0 , 01 ) SK sup F ( $ i ) – F ( $ i ) ) , where the supremum is taken over
those i and j for which 0 , 0 , is not void . If by the norm 71 is understood the ...
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Contents
SPECTRAL OPERATORS | 1924 |
An Operational Calculus for Bounded Spectral | 1941 |
Part | 1950 |
Copyright | |
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