Linear Operators: Spectral operators |
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Page 2232
Since Q is closed , it follows that x is in D ( Q ) and that Qx = Qx . Thus Q SQ . It
follows from symmetry that Q = Q . Q . E . D . 7 COROLLARY . Under the
hypotheses of the preceding theorem it follows that E ( e ) D ( Q ) & D ( Q ) and
QE ( e ) x ...
Since Q is closed , it follows that x is in D ( Q ) and that Qx = Qx . Thus Q SQ . It
follows from symmetry that Q = Q . Q . E . D . 7 COROLLARY . Under the
hypotheses of the preceding theorem it follows that E ( e ) D ( Q ) & D ( Q ) and
QE ( e ) x ...
Page 2396
Let 04 be as in the preceding lemma , put A ( a ) = A ( 0 ( : , f ( a ) ) ) , and let B ( A
) = A ( 04 ( : , M ( A ) ) ) ( cf . Lemma 4 for the definition of u ( a ) ) . Then , by the
preceding lemma , by Lemma 1 , and by formulas ( 2a ) and ( 2b ) , ( B ( 2 ) ~ | A )
...
Let 04 be as in the preceding lemma , put A ( a ) = A ( 0 ( : , f ( a ) ) ) , and let B ( A
) = A ( 04 ( : , M ( A ) ) ) ( cf . Lemma 4 for the definition of u ( a ) ) . Then , by the
preceding lemma , by Lemma 1 , and by formulas ( 2a ) and ( 2b ) , ( B ( 2 ) ~ | A )
...
Page 2455
Therefore , if we let the three operators of the preceding lemma be H2 , H1 , H1 ,
we obtain the present corollary . Q . E . D . 5 COROLLARY . Under the
hypotheses of the preceding corollary , U ( H1 , H2 ) is an isometric mapping of E
( H1 , H2 ) ...
Therefore , if we let the three operators of the preceding lemma be H2 , H1 , H1 ,
we obtain the present corollary . Q . E . D . 5 COROLLARY . Under the
hypotheses of the preceding corollary , U ( H1 , H2 ) is an isometric mapping of E
( H1 , H2 ) ...
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Contents
SPECTRAL OPERATORS 1937 1941 1945 XV Spectral Operators | 1924 |
Introduction | 1927 |
Terminology and Preliminary Notions | 1929 |
Copyright | |
29 other sections not shown
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