## Linear Operators: Spectral operators |

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Let D be a dense ideal in B and m be a function on D to cardinals such that m ( 0 ) = 0 and m ( Væ Ec ) = Vam ( Ec ) for each family { Ex } $ D for which V & E , E D. Then there is a unique

Let D be a dense ideal in B and m be a function on D to cardinals such that m ( 0 ) = 0 and m ( Væ Ec ) = Vam ( Ec ) for each family { Ex } $ D for which V & E , E D. Then there is a unique

**multiplicity**function on B which is an ...Page 2283

Then a projection E in B has finite uniform

Then a projection E in B has finite uniform

**multiplicity**n if and only if its adjoint E * in B * has finite uniform**multiplicity**n . PROOF . It is sufficient to suppose E and E * satisfy the countable chain condition .Page 2288

J . Dieudonné [ 20 ] had previously obtained a

J . Dieudonné [ 20 ] had previously obtained a

**multiplicity**theory in the case where the adjoint X * of the underlying Banach space X is separable ( which implies the separability of X ) . In connection with Lemma 3.18 we note that in ...### What people are saying - Write a review

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### Contents

SPECTRAL OPERATORS 1937 1941 1945 XV Spectral Operators | 1924 |

Introduction | 1927 |

Terminology and Preliminary Notions | 1929 |

Copyright | |

32 other sections not shown

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adjoint operator Amer analytic apply arbitrary assumed B-space Banach space belongs Boolean algebra Borel set boundary conditions bounded bounded operator Chapter clear closed commuting compact complex constant contains continuous converges Corollary corresponding countably additive defined Definition denote dense determined differential operator domain elements equation equivalent established exists extension fact finite follows formal formula function given gives Hence Hilbert space hypothesis identity inequality integral invariant inverse Lemma limit linear operator Math Moreover multiplicity norm perturbation plane positive preceding present problem projections PROOF properties prove range resolution resolvent restriction Russian satisfies scalar type seen sequence shown shows similar solution spectral measure spectral operator spectrum subset sufficiently Suppose Theorem theory topology unbounded uniformly unique valued vector zero