Linear Operators: Spectral operators |
From inside the book
Results 1-3 of 60
Page 1967
Hence \ u ] = lim | um | 1 / n = lim | vn | 1 / n = lvl . Q . E . D . 2 LEMMA . If a B * -
subalgebra X of a B * - algebra Y has the same unit e as V , then an element in X
with an inverse in Y has this inverse also in X . PROOF . We first show that e = e *
.
Hence \ u ] = lim | um | 1 / n = lim | vn | 1 / n = lvl . Q . E . D . 2 LEMMA . If a B * -
subalgebra X of a B * - algebra Y has the same unit e as V , then an element in X
with an inverse in Y has this inverse also in X . PROOF . We first show that e = e *
.
Page 2065
Since , for a in A , , the function â is continuous on the compact space S , it follows
that an operator a in A , has an inverse in A if à ( s ) does not vanish on S . A
celebrated theorem of N . Wiener gives more by asserting that the inverse a - 1 is
in ...
Since , for a in A , , the function â is continuous on the compact space S , it follows
that an operator a in A , has an inverse in A if à ( s ) does not vanish on S . A
celebrated theorem of N . Wiener gives more by asserting that the inverse a - 1 is
in ...
Page 2069
Let the operator a in A have an inverse in B ( H ) . If a is of type ... 0 Sk 500 , then
the inverse a - 1 has this same property . ... 6 , A - 1 is in AP and the determinant
S = det ( ay ) has an inverse in A . Since A , contains all inverses , 8 - 1 is in A . .
Let the operator a in A have an inverse in B ( H ) . If a is of type ... 0 Sk 500 , then
the inverse a - 1 has this same property . ... 6 , A - 1 is in AP and the determinant
S = det ( ay ) has an inverse in A . Since A , contains all inverses , 8 - 1 is in A . .
What people are saying - Write a review
We haven't found any reviews in the usual places.
Contents
SPECTRAL OPERATORS | 1924 |
An Operational Calculus for Bounded Spectral | 1941 |
Part | 1950 |
Copyright | |
9 other sections not shown
Other editions - View all
Common terms and phrases
adjoint operator analytic apply arbitrary assume B-space Banach space Boolean algebra Borel sets boundary conditions bounded bounded operator Chapter clear closed commuting compact complex consider constant contained continuous converges Corollary corresponding countably additive defined Definition denote dense determined differential operator discrete domain elements equation equivalent established example exists extension fact finite follows formal formula given gives Hence Hilbert space hypothesis identity inequality integral invariant inverse Lemma limit linear linear operator Math Moreover multiplicity norm positive preceding present problem projections PROOF properties proved range regular resolution resolvent respectively restriction Russian satisfies scalar type seen sequence shown shows similar spectral measure spectral operator spectrum subset subspace sufficiently Suppose Theorem theory topology unbounded uniform uniformly unique valued vector weakly zero