## Linear Operators: Spectral operators |

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Page 2017

Nelson Dunford, Jacob T. Schwartz, William G. Bade, Robert G. Bartle. and the

fraction in the

1681 s } 1 / 2 which is bounded on all of R " . Thus As has a resolution of the

identity .

Nelson Dunford, Jacob T. Schwartz, William G. Bade, Robert G. Bartle. and the

fraction in the

**inequality**( i ) of Theorem 6 is Isi - s2l2 + 2 | 818212 { ( si - 2 ) +1681 s } 1 / 2 which is bounded on all of R " . Thus As has a resolution of the

identity .

Page 2190

Thus for some constant K we have $ ( f ) SK \ f and to prove the final

the present theorem it will suffice to prove that Ife SS ( $ ) . Since both terms in

this

Thus for some constant K we have $ ( f ) SK \ f and to prove the final

**inequality**ofthe present theorem it will suffice to prove that Ife SS ( $ ) . Since both terms in

this

**inequality**are continuous functions of f , it will suffice to prove it for every ...Page 2403

First we shall prove an

is elementary in the sense that it relates only to the norms of the integral kernels

involved . We then use this

First we shall prove an

**inequality**for integral operators ( Lemma 5 below ) whichis elementary in the sense that it relates only to the norms of the integral kernels

involved . We then use this

**inequality**to apply Theorem 1 in an illustrative but ...### What people are saying - Write a review

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### Contents

SPECTRAL OPERATORS | 1924 |

An Operational Calculus for Bounded Spectral | 1941 |

Part | 1950 |

Copyright | |

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