## Linear Operators: Spectral operators |

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and the fraction in the

and the fraction in the

**inequality**( i ) of Theorem 6 is Isi - sl ? + 2 | 818212 { ( si - 2 ) * + 1681 $ } 1/2 which is bounded on all of R " . Thus As has a resolution of the identity . Furthermore , the set S , is the null set { s ...Page 2190

Thus for some constant K we have | S ( f ) | SK \ f | and to prove the final

Thus for some constant K we have | S ( f ) | SK \ f | and to prove the final

**inequality**of the present theorem it will suffice to prove that Ifle = S ( $ ) . Since both terms in this**inequality**are continuous functions of f , it will ...Page 2403

First we shall prove an

First we shall prove an

**inequality**for integral operators ( Lemma 5 below ) which is elementary in the sense that it relates only to the norms of the integral kernels involved . We then use this**inequality**to apply Theorem 1 in an ...### What people are saying - Write a review

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### Contents

SPECTRAL OPERATORS 1937 1941 1945 XV Spectral Operators | 1924 |

Introduction | 1927 |

Terminology and Preliminary Notions | 1929 |

Copyright | |

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