Linear Operators: Spectral operators |
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Page 1931
... extension , ƒ ( § ) = R ( § ; T ) x , έe D ( f ) . ξερ ( Τ ) . The notion of " analytic extension " differs from that of " analytic con- tinuation , " for the domain D ( f ) of an extension may contain points which cannot be connected ...
... extension , ƒ ( § ) = R ( § ; T ) x , έe D ( f ) . ξερ ( Τ ) . The notion of " analytic extension " differs from that of " analytic con- tinuation , " for the domain D ( f ) of an extension may contain points which cannot be connected ...
Page 2092
... extension property . The example of an operator which does not have the single valued extension property that is given in Section 2 is due to S. Kakutani ( see Dunford [ 18 ] ) . Kesel'man [ 1 ] gave necessary conditions for an operator ...
... extension property . The example of an operator which does not have the single valued extension property that is given in Section 2 is due to S. Kakutani ( see Dunford [ 18 ] ) . Kesel'man [ 1 ] gave necessary conditions for an operator ...
Page 2095
... extension property have this property ( see Dowson [ 1 ] ) , the corresponding result for quotients is not true . Indeed , Dowson [ 3 ] notes that the unitary shift operator has quotients which do not have the single valued extension ...
... extension property have this property ( see Dowson [ 1 ] ) , the corresponding result for quotients is not true . Indeed , Dowson [ 3 ] notes that the unitary shift operator has quotients which do not have the single valued extension ...
Contents
SPECTRAL OPERATORS | 1924 |
Spectral Operators | 1925 |
Terminology and Preliminary Notions | 1928 |
Copyright | |
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A₁ algebra Amer analytic applications arbitrary B-space Banach Banach space Boolean algebra Borel sets boundary bounded Chapter clear closed commuting compact complex constant contains continuous converges Corollary corresponding defined Definition denote dense determined differential operator Doklady Akad elements equation equivalent established example exists extension finite follows formula function given gives H₁ Hence Hilbert space hypothesis identity integral invariant inverse Lemma limit linear operators Math multiplicity Nauk SSSR norm normal perturbation plane positive preceding present problem Proc projections PROOF properties prove range resolution resolvent restriction Russian satisfies scalar type sequence shown shows similar spectral measure spectral operator spectrum subset subspace sufficiently Suppose Theorem theory topology unbounded uniformly unique valued vector zero