## Linear Operators: Part III: Spectral Operators [by] Nelson Dunford and Jacob T. Schwartz, with the Assistance of William G. Bade and Robert G. Bartle, Volume 1 |

### From inside the book

Results 1-3 of 91

Page 2084

57 ( McCarthy ) Let T be a spectral operator in a

57 ( McCarthy ) Let T be a spectral operator in a

**complex**B - spaceX satisfying the mth order condition ( * ) . If N is the radical part of T , then Nm + 2 = 0 . 58 ( McCarthy ) Let T be a spectral operator in a**complex**B - spaceX which ...Page 2171

The symbol T is a bounded linear operator on a

The symbol T is a bounded linear operator on a

**complex**B - space X. For each x in & the symbol [ x ] will be used for the closed linear manifold determined by all the vectors R ( E ; T ) x with & in p ( T ) .Page 2188

Let E be a spectral measure in the

Let E be a spectral measure in the

**complex**B - space X which is defined and countably additive on a o - field of subsets of a set 1 and let g be a bounded Borel measurable function defined on the**complex**plane .### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Contents

SPECTRAL OPERATORS | 1924 |

Introduction | 1927 |

Terminology and Preliminary Notions | 1929 |

Copyright | |

47 other sections not shown

### Other editions - View all

### Common terms and phrases

adjoint operator Amer analytic apply arbitrary assumed B-space Banach space belongs Boolean algebra Borel set boundary conditions bounded bounded operator Chapter clear closed commuting compact complex constant contains continuous converges Corollary corresponding defined Definition denote dense determined differential operator domain elements equation equivalent established exists extension finite follows formal formula given gives Hence Hilbert space hypothesis identity inequality integral invariant inverse Lemma limit linear operator Math Moreover multiplicity norm perturbation plane positive preceding present problem projections PROOF properties prove range resolution resolvent restriction Russian satisfies scalar type seen sequence shown shows similar solution spectral measure spectral operator spectrum subset sufficiently Suppose Theorem theory topology unbounded uniformly unique valued vector zero