## Linear Operators: Part III: Spectral Operators [by] Nelson Dunford and Jacob T. Schwartz, with the Assistance of William G. Bade and Robert G. Bartle, Volume 1 |

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Page 2313

This is because in Hilbert space we use the Hermitian rather than the pure

This is because in Hilbert space we use the Hermitian rather than the pure

**Banach space**adjoint , contrary to our practice in other**Banach spaces**. This has the effect of introducing complex conjugates in many of the Hilbert - space ...Page 2514

Some properties of spectral maximal spaces and decomposable operators . Rev. Roumaine Math . Pures Appl . 12 , 607–610 ( 1967 ) . 16. Some properties of a couple of operators on a

Some properties of spectral maximal spaces and decomposable operators . Rev. Roumaine Math . Pures Appl . 12 , 607–610 ( 1967 ) . 16. Some properties of a couple of operators on a

**Banach space**. Rev. Roumaine Math .Page 2528

Finite dimensional perturbations in

Finite dimensional perturbations in

**Banach spaces**. Amer . J. Math . ... Weak limits of powers of a contraction in Hilbert space . Proc . Amer . Math . Soc . ... On spectrality criterion for operators on a direct sum of Hilbert spaces .### What people are saying - Write a review

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### Contents

SPECTRAL OPERATORS | 1924 |

Introduction | 1927 |

Terminology and Preliminary Notions | 1929 |

Copyright | |

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### Common terms and phrases

adjoint operator Amer analytic apply arbitrary assumed B-space Banach space belongs Boolean algebra Borel set boundary conditions bounded bounded operator Chapter clear closed commuting compact complex constant contains continuous converges Corollary corresponding defined Definition denote dense determined differential operator domain elements equation equivalent established exists extension finite follows formal formula given gives Hence Hilbert space hypothesis identity inequality integral invariant inverse Lemma limit linear operator Math Moreover multiplicity norm perturbation plane positive preceding present problem projections PROOF properties prove range resolution resolvent restriction Russian satisfies scalar type seen sequence shown shows similar solution spectral measure spectral operator spectrum subset sufficiently Suppose Theorem theory topology unbounded uniformly unique valued vector zero