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Page 293
lim , ( s ) u ( ds ) = 0 is uniform for f in K . Assume now that K is weakly
sequentially compact . It follows from Lemma II . 3 . 27 that K is bounded . If the
integrals Sel ( s ) u ( ds ) are not countably additive uniformly with respect to f in K
there is a ...
lim , ( s ) u ( ds ) = 0 is uniform for f in K . Assume now that K is weakly
sequentially compact . It follows from Lemma II . 3 . 27 that K is bounded . If the
integrals Sel ( s ) u ( ds ) are not countably additive uniformly with respect to f in K
there is a ...
Page 294
... 2 E , we can find a subset An of En such that Ja tu ( s ) u ( ds ) 2 € / 2 . Since K
is weakly sequentially compact , a subsequence of { { n } converges weakly , and
it may be assumed without loss of generality that { / n } itself converges weakly .
... 2 E , we can find a subset An of En such that Ja tu ( s ) u ( ds ) 2 € / 2 . Since K
is weakly sequentially compact , a subsequence of { { n } converges weakly , and
it may be assumed without loss of generality that { / n } itself converges weakly .
Page 314
Q.E.D. 12 THEOREM . A subset K of ba ( S , ) is weakly sequentially compact if
and only if there exists a non - negative u in ba ( S , E ) such that lim 2 ( E ) = 0
unifarmly for à e K. PROOF . Let K C ba ( S , ) be weakly sequentially compact
and let ...
Q.E.D. 12 THEOREM . A subset K of ba ( S , ) is weakly sequentially compact if
and only if there exists a non - negative u in ba ( S , E ) such that lim 2 ( E ) = 0
unifarmly for à e K. PROOF . Let K C ba ( S , ) be weakly sequentially compact
and let ...
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Contents
Preliminary Concepts | 1 |
B Topological Preliminaries | 10 |
Algebraic Preliminaries | 34 |
Copyright | |
80 other sections not shown
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algebra Amer analytic applied arbitrary assumed B-space Banach Banach spaces bounded called clear closed compact complex condition contains continuous functions converges convex Corollary countably additive defined DEFINITION denote dense determined differential disjoint Doklady Akad element equation equivalent everywhere Exercise exists extension field finite follows function defined function f given Hence Hilbert space implies inequality integral interval isomorphism Lebesgue Lemma limit linear functional linear operator linear space mapping Math meaning measure space metric neighborhood norm operator positive measure problem Proc proof properties proved respect Russian satisfies scalar seen separable sequence set function Show shown sphere statement subset sufficient Suppose Theorem theory topological space topology transformations u-measurable uniform uniformly unique unit valued vector weak weakly compact zero