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Page 262
Since the integral Ss ( s ) u ( ds ) satisfies the inequality 1st ( s ) u ( ds ) < sup \ | (
s ) [ 0 ( 4 , S ) , it is clear that the ... an isometric isomorphism between C * ( S )
and rba ( S ) such that corresponding elements w * and u satisfy the identity u ( ds
) ...
Since the integral Ss ( s ) u ( ds ) satisfies the inequality 1st ( s ) u ( ds ) < sup \ | (
s ) [ 0 ( 4 , S ) , it is clear that the ... an isometric isomorphism between C * ( S )
and rba ( S ) such that corresponding elements w * and u satisfy the identity u ( ds
) ...
Page 495
Since B , is an algebra and satisfies condition ( ii ) , it is readily seen that B , is a o
- field contained in B. We now show that B. B by proving that B , contains all the
closed sets . Let F be an arbitrary closed set in S. Since S is assumed to be a ...
Since B , is an algebra and satisfies condition ( ii ) , it is readily seen that B , is a o
- field contained in B. We now show that B. B by proving that B , contains all the
closed sets . Let F be an arbitrary closed set in S. Since S is assumed to be a ...
Page 613
... continuous real ( or complex ) function f of the nonnegative real variable t
which satisfies the functional equations f ( 0 ) ... the most general continuous
operator valued functions defined on the range t 20 , which satisfy the equations (
i ) T ( t + ...
... continuous real ( or complex ) function f of the nonnegative real variable t
which satisfies the functional equations f ( 0 ) ... the most general continuous
operator valued functions defined on the range t 20 , which satisfy the equations (
i ) T ( t + ...
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Contents
Preliminary Concepts | 1 |
B Topological Preliminaries | 10 |
Algebraic Preliminaries | 34 |
Copyright | |
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algebra Amer analytic applied arbitrary assumed B-space Banach Banach spaces bounded called clear closed compact complex condition contains continuous functions converges convex Corollary countably additive defined DEFINITION denote dense determined differential disjoint Doklady Akad element equation equivalent everywhere Exercise exists extension field finite follows function defined function f given Hence Hilbert space implies inequality integral interval isomorphism Lebesgue Lemma limit linear functional linear operator linear space mapping Math meaning measure space metric neighborhood norm operator positive measure problem Proc proof properties proved respect Russian satisfies scalar seen separable sequence set function Show shown sphere statement subset sufficient Suppose Theorem theory topological space topology transformations u-measurable uniform uniformly unique unit valued vector weak weakly compact zero