## Linear Operators: Spectral theory |

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Page 1310

Then the boundary conditions are real , and there is exactly one solution q ( t , 2 )

of ( T - 219 = 0

a , and exactly one solution y ( t , 2 ) of ( T - 2 ) = 0

Then the boundary conditions are real , and there is exactly one solution q ( t , 2 )

of ( T - 219 = 0

**square**-**integrable**at a and satisfying the boundary conditions ata , and exactly one solution y ( t , 2 ) of ( T - 2 ) = 0

**square**-**integrable**at b and ...Page 1329

Let In +0 . Then the boundary conditions are real , and there is exactly one

solution q ( t , 2 ) of ( 1-2 ) = 0

conditions at a , and exactly one solution y ( t , 2 ) of ( T - 1 ) 0 = 0

Let In +0 . Then the boundary conditions are real , and there is exactly one

solution q ( t , 2 ) of ( 1-2 ) = 0

**square**-**integrable**at a and satisfying the boundaryconditions at a , and exactly one solution y ( t , 2 ) of ( T - 1 ) 0 = 0

**squareintegrable**at ...Page 1416

Because fı is positive , and not

equation to = 0 is

t2 be a ...

Because fı is positive , and not

**square**-**integrable**, f cannot be**square**-**integrable**. ( b ) By Theorem 11 , it will suffice to show that every solution of theequation to = 0 is

**square**-**integrable**. Let | be a real solution of this equation . Lett2 be a ...

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### Contents

SPECTRAL THEORY Self Adjoint Operators in Hilbert Space | 858 |

BAlgebras | 859 |

Commutative BAlgebras | 868 |

Copyright | |

57 other sections not shown

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