A Key to Dilworth's Arithmetic: Wherein Every Question is Worked Out at Full Length ... Adapted to the American Arithmetician |
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Page 28 - They are these : • 1. Divide the second term by the first, multiply the quotient by the third, and the product will be the answer. 2. Divide the third term by the first, multiply the quotient by the second, and the product will be the answer. , 3. Divide the first term by the second, divide the third by the quotient, and the last quotient will be the.
Page 28 - Divide the second term by the first, multiply the quotient by the third, and the product will be the answer. 3. Divide the third term by the first, multiply the quotient by the second, and the product will be the answer. 4. Divide the first term by the second, and the third by that quotient, the last quotient will be the answer.
Page 134 - ... of additions, that is by 1 less than the number of terms, and add the first term to the product. Hence, we have CASE I.
Page 136 - CASE tt 344. Given the first term, the ratio, and the number of terms, to find the sum of the terms. Let a denote the first term, r the ratio, n the number of terms, and i- the sum of the terms. Then, S = a + ar + ar...