Linear Operators, Part 2 |
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Page 1250
Finally we show that the decomposition T = PA of the theorem is unique . ... Since
A is unique , P is uniquely determined on R ( A ) by the equation of P ( Ax ) = Tx .
Further the extension of P by continuity from R ( A ) to R ( A ) is unique . Since P ...
Finally we show that the decomposition T = PA of the theorem is unique . ... Since
A is unique , P is uniquely determined on R ( A ) by the equation of P ( Ax ) = Tx .
Further the extension of P by continuity from R ( A ) to R ( A ) is unique . Since P ...
Page 1283
Thus , equation ( e ' ) has the unique solution ( cf . Lemma VII . 3 . 4 ) F = ( 1 + 0 ) -
H = ( - 1 ) P H . j = 0 Since all the terms in equation ( e ) but the first are absolutely
continuous , it follows that F is absolutely continuous . Thus Theorem 1 is ...
Thus , equation ( e ' ) has the unique solution ( cf . Lemma VII . 3 . 4 ) F = ( 1 + 0 ) -
H = ( - 1 ) P H . j = 0 Since all the terms in equation ( e ) but the first are absolutely
continuous , it follows that F is absolutely continuous . Thus Theorem 1 is ...
Page 1383
With boundary conditions A and C , the unique solution of 730 = ho satisfying the
boundary condition 130 = ho is sin vīt . With boundary conditions A , the
eigenvalues are consequently to be determined from the equation sin vă = 0 .
With boundary conditions A and C , the unique solution of 730 = ho satisfying the
boundary condition 130 = ho is sin vīt . With boundary conditions A , the
eigenvalues are consequently to be determined from the equation sin vă = 0 .
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Contents
BAlgebras | 859 |
Commutative BAlgebras | 868 |
Commutative BAlgebras | 874 |
Copyright | |
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