## Linear Operators, Volume 2 |

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Page 1310

Then the boundary conditions are real , and there is exactly one solution p ( t , 2 ) of ( 1-2 ) = 0

Then the boundary conditions are real , and there is exactly one solution p ( t , 2 ) of ( 1-2 ) = 0

**square**-**integrable**at a and satisfying the boundary conditions at a , and exactly one solution y ( t , 2 ) of ( 1-2 ) = 0**square**...Page 1329

Then the boundary conditions are real , and there is exactly one solution p ( t , 2 ) of ( 1-2 ) 0 = 0

Then the boundary conditions are real , and there is exactly one solution p ( t , 2 ) of ( 1-2 ) 0 = 0

**square**-**integrable**at a and satisfying the boundary conditions at a , and exactly one solution y ( t , 2 ) of ( 1-2 ) = 0 ...Page 1552

Prove that the equation of = 0 has a

Prove that the equation of = 0 has a

**square**-**integrable**solution . G2 ( Wintner ) Suppose that the operator has the property that whenever f is a**square**-**integrable**solution of the equation ( 2-7 ) } = 0 , then f ' is also**square**...### What people are saying - Write a review

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### Contents

BAlgebras | 859 |

Commutative BAlgebras | 868 |

Commutative BAlgebras | 874 |

Copyright | |

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additive adjoint operator algebra Amer analytic assume Banach spaces basis belongs Borel boundary conditions boundary values bounded called clear closed closure coefficients compact complex Consequently constant contains continuous converges Corollary corresponding defined Definition denote dense derivatives determined domain eigenvalues element equal equation essential spectrum evident Exercise exists extension finite follows formal differential operator formula function function f given Hence Hilbert space identity independent indices inequality integral interval Lemma limit linear mapping Math matrix measure multiplicity neighborhood norm obtained partial positive preceding present problem projection proof properties prove range regular remark representation respectively restriction result satisfies seen sequence shown singular solution spectral square-integrable statement subset subspace sufficiently Suppose symmetric Theorem theory topology transform unique vanishes vector zero