## Linear Operators, Part 2 |

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Page 1310

Then the boundary conditions are real , and there is exactly one solution p ( t , 2 )

of ( 1 – 2 ) 9 = 0

a , and exactly one solution y ( t , 2 ) of ( 1 - 2 ) y = 0

Then the boundary conditions are real , and there is exactly one solution p ( t , 2 )

of ( 1 – 2 ) 9 = 0

**square**-**integrable**at a and satisfying the boundary conditions ata , and exactly one solution y ( t , 2 ) of ( 1 - 2 ) y = 0

**square**-**integrable**at b ...Page 1329

Then the boundary conditions are real , and there is exactly one solution o ( t , 2 )

of ( 7 - 2 ) 0 = 0

a , and exactly one solution y ( t , 2 ) of ( 1 - 2 ) 0 = 0

Then the boundary conditions are real , and there is exactly one solution o ( t , 2 )

of ( 7 - 2 ) 0 = 0

**square**-**integrable**at a and satisfying the boundary conditions ata , and exactly one solution y ( t , 2 ) of ( 1 - 2 ) 0 = 0

**squareintegrable**at b ...Page 1552

Prove that the equation tf = 0 has a

Suppose that the operator t has the property that whenever f is a

.

Prove that the equation tf = 0 has a

**square**-**integrable**solution . G2 ( Wintner )Suppose that the operator t has the property that whenever f is a

**square**-**integrable**solution of the equation ( 2 - 1 ) } = 0 , then f is also**square**-**integrable**.

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### Contents

BAlgebras | 859 |

Commutative BAlgebras | 868 |

Commutative BAlgebras | 874 |

Copyright | |

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