## Linear Operators, Part 2 |

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Page 1310

Then the boundary

of ( 1 – 2 ) 9 = 0 square - integrable at a and satisfying the boundary ... In case ( iii

) , one boundary

Then the boundary

**conditions**are real , and there is exactly one solution p ( t , 2 )of ( 1 – 2 ) 9 = 0 square - integrable at a and satisfying the boundary ... In case ( iii

) , one boundary

**condition**is to be imposed , since , according to Theorem XII .Page 1471

31 , a set of boundary

the form B ( f ) = QG ( ) + Q2 G2 ( t ) ... ( T ( Tı ) ) satisfy the boundary

) = 0 , or if + has no boundary values at a and f , g e D ( Tı ( tı ) ) , then ( 11 ) , g ...

31 , a set of boundary

**conditions**defining a self adjoint restriction T of T ( T ) is ofthe form B ( f ) = QG ( ) + Q2 G2 ( t ) ... ( T ( Tı ) ) satisfy the boundary

**condition**B ( f) = 0 , or if + has no boundary values at a and f , g e D ( Tı ( tı ) ) , then ( 11 ) , g ...

Page 1472

On the other hand , if two linearly independent solutions of to = lo satisfy the

boundary

remark ( a ) made above , it then follows that for any two solutions f , g of to = lo ,

and a < c ...

On the other hand , if two linearly independent solutions of to = lo satisfy the

boundary

**condition**B , it follows that all solutions of to = ho satisfy B . By theremark ( a ) made above , it then follows that for any two solutions f , g of to = lo ,

and a < c ...

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### Contents

BAlgebras | 859 |

Commutative BAlgebras | 868 |

Commutative BAlgebras | 874 |

Copyright | |

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