## Linear Operators, Volume 2 |

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Page 1083

Consequently , the series 4 ( 2 ) -18 ( 2 ) 1 = 4,2 " n = 2 of the preceding

Consequently , the series 4 ( 2 ) -18 ( 2 ) 1 = 4,2 " n = 2 of the preceding

**exercise**converges in the Hilbert - Schmidt norm . 44 Let ( S , E , u ) be a positive measure space . Then an operator A in the Hilbert space L2 ( S ...Page 1086

Show , finally , that by choosing As , 8 ) = 0 for all s in S , we obtain the result of

Show , finally , that by choosing As , 8 ) = 0 for all s in S , we obtain the result of

**Exercise**46 as a special case of the present result . ( Hint : Generalize the method of**Exercise**46. ) 49 The operator A of Hilbert - Schmidt class ...Page 1087

( Hint : For ( d ) , use Weyl's inequality ,

( Hint : For ( d ) , use Weyl's inequality ,

**Exercise**30. ) E. Miscellaneous**Exercises**50 ( Halberg ) Let ( S , E , u ) be a o - finite measure space . Let T , be a 1 - parameter family of bounded operators defined in a subinterval I of ...### What people are saying - Write a review

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### Contents

BAlgebras | 859 |

Commutative BAlgebras | 868 |

Commutative BAlgebras | 874 |

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additive adjoint operator algebra Amer analytic assume Banach spaces basis belongs Borel boundary conditions boundary values bounded called clear closed closure coefficients compact complex Consequently constant contains continuous converges Corollary corresponding defined Definition denote dense derivatives determined domain eigenvalues element equal equation essential spectrum evident Exercise exists extension finite follows formal differential operator formula function function f given Hence Hilbert space identity independent indices inequality integral interval Lemma limit linear mapping Math matrix measure multiplicity neighborhood norm obtained partial positive preceding present problem projection proof properties prove range regular remark representation respectively restriction result satisfies seen sequence shown singular solution spectral square-integrable statement subset subspace sufficiently Suppose symmetric Theorem theory topology transform unique vanishes vector zero