## Linear Operators: General theory |

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Page 20

Thus 4 , + X , and A is open , and

Thus 4 , + X , and A is open , and

**contains**a sphere s S ( P1 , & j ) with 0 < x < 1/2 . By assumption , the set A , does not**contain**the open set S ( P1 ...Page 56

of the image of any neighborhood G of the element 0 in X

of the image of any neighborhood G of the element 0 in X

**contains**a neighborhood of the element 0 in Y. Since a -- b is a continuous function of a and b ...Page 309

The set A S - U E ; then

The set A S - U E ; then

**contains**no atoms having measure greater than ε . It will now be shown that every measurable subset B of A**contains**a set F with 0 ...### What people are saying - Write a review

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### Contents

B Topological Preliminaries | 10 |

quences | 26 |

Algebraic Preliminaries | 34 |

Copyright | |

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Acad algebra Amer analytic applied arbitrary assumed B-space Banach Banach spaces bounded called clear closed compact complex condition contains continuous functions converges convex Corollary countably additive defined DEFINITION denote dense determined differential disjoint Doklady Akad element equation equivalent everywhere Exercise exists extension field finite follows function defined function f given Hence Hilbert space implies inequality integral interval isomorphism Lebesgue Lemma limit linear functional linear operator linear space mapping Math meaning measure space metric neighborhood norm operator positive measure problem Proc PROOF properties proved respect Russian satisfies scalar seen semi-group separable sequence set function Show shown sphere statement subset sufficient Suppose Theorem theory topological space topology transformations u-measurable uniform uniformly unique unit valued vector weak weakly compact zero