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Page 20
Thus A1 + X , and A is open , and contains a sphere Si = S ( P1 , & z ) with 0 < & i
< 1 / 2 . By assumption , the set A , does not contain the open set S ( P1 , & z / 2 ) ;
hence the non - void open set An S ( P1 , & z / 2 ) contains a sphere S , = S ( P2 ...
Thus A1 + X , and A is open , and contains a sphere Si = S ( P1 , & z ) with 0 < & i
< 1 / 2 . By assumption , the set A , does not contain the open set S ( P1 , & z / 2 ) ;
hence the non - void open set An S ( P1 , & z / 2 ) contains a sphere S , = S ( P2 ...
Page 56
of the image of any neighborhood G of the element 0 in X contains a
neighborhood of the element 0 in Y . Since a - b is a continuous function of a and
b , there is a neighborhood M of 0 such that M - MCG . For every x e X , æ / n + 0 ,
and so x e ...
of the image of any neighborhood G of the element 0 in X contains a
neighborhood of the element 0 in Y . Since a - b is a continuous function of a and
b , there is a neighborhood M of 0 such that M - MCG . For every x e X , æ / n + 0 ,
and so x e ...
Page 309
The set A = S - U - E ; then contains no atoms having measure greater than ε . It
will now be shown that every measurable subset B of A contains a set F with 0 ) <
u ( F ) 3 € . Suppose , on the contrary , that some such set B contains no set of ...
The set A = S - U - E ; then contains no atoms having measure greater than ε . It
will now be shown that every measurable subset B of A contains a set F with 0 ) <
u ( F ) 3 € . Suppose , on the contrary , that some such set B contains no set of ...
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Contents
Metric Spaces | 19 |
Convergence and Uniform Convergence of Generalized | 26 |
Exercises | 33 |
Copyright | |
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Acad algebra Amer analytic applied arbitrary assumed B-space Banach Banach spaces bounded called clear closed compact complex contains continuous functions converges convex Corollary countably additive defined DEFINITION denote dense determined differential disjoint Doklady Akad domain elements equation equivalent everywhere Exercise exists extension field finite follows function defined function f given Hence Hilbert space implies inequality integral interval isomorphism Lebesgue Lemma limit linear functional linear operator linear space mapping Math mean measure space metric space neighborhood norm operator positive problem Proc PROOF properties proved range regular respect Russian satisfies scalar seen semi-group separable sequence set function Show shown sphere statement subset Suppose Theorem theory topological space topology transformations u-integrable u-measurable uniformly union unique unit valued vector weak zero