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Page 262
Since the integral [ st ( s ) u ( ds ) satisfies the inequality sup \ | ( s ) [ v ( u , S ) , it is
clear that the integral is a continuous linear functional on C ( S ) . The following
theorem is a converse to this statement . 2 THEOREM . If S is normal , there is an
...
Since the integral [ st ( s ) u ( ds ) satisfies the inequality sup \ | ( s ) [ v ( u , S ) , it is
clear that the integral is a continuous linear functional on C ( S ) . The following
theorem is a converse to this statement . 2 THEOREM . If S is normal , there is an
...
Page 282
It is clear that T ( 8 ) C T ( d ) if ε < d and that - te T ( E ) whenever te T ( € ) . The
function f is said to be almost periodic if it is continuous and if for every e > 0 there
is an L = L ( 8 ) > 0 such that every interval in R of length L contains at least one ...
It is clear that T ( 8 ) C T ( d ) if ε < d and that - te T ( E ) whenever te T ( € ) . The
function f is said to be almost periodic if it is continuous and if for every e > 0 there
is an L = L ( 8 ) > 0 such that every interval in R of length L contains at least one ...
Page 292
It is clear that if F , and F , are elements of £3 , then F , F , € £g . It is also clear that
if F4 € £g , then S - F , € £g , and that if F1 , F2 € £z with F F , = 0 , then Fi UF , € £
g . It follows that Ez is a field . If { Fx } is a sequence of disjoint elements of Eg ...
It is clear that if F , and F , are elements of £3 , then F , F , € £g . It is also clear that
if F4 € £g , then S - F , € £g , and that if F1 , F2 € £z with F F , = 0 , then Fi UF , € £
g . It follows that Ez is a field . If { Fx } is a sequence of disjoint elements of Eg ...
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Contents
Metric Spaces | 19 |
Convergence and Uniform Convergence of Generalized | 26 |
Exercises | 33 |
Copyright | |
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