## Linear Operators: Part III: Spectral Operators [by] Nelson Dunford and Jacob T. Schwartz, with the Assistance of William G. Bade and Robert G. Bartle, Volume 1 |

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Results 1-3 of 69

Page 2017

and the fraction in the

closed operator As cannot be self adjoint , but it always has a resolution of the

identity for 8 ( 8 ) = ( 87 – 83 ) + 4a8 , so that the

holds .

and the fraction in the

**inequality**( i ) of Theorem 6 is 1si - sl ? ... correspondingclosed operator As cannot be self adjoint , but it always has a resolution of the

identity for 8 ( 8 ) = ( 87 – 83 ) + 4a8 , so that the

**inequality**( i ) of Theorem 6holds .

Page 2190

From the preceding lemma it is seen that the map f→ S ( f ) is a continuous

homomorphism of EB ( 1 , 2 ) onto an algebra of scalar type spectral operators .

Thus for some constant K we have | S ( ) < K \ f | and to prove the final

of the ...

From the preceding lemma it is seen that the map f→ S ( f ) is a continuous

homomorphism of EB ( 1 , 2 ) onto an algebra of scalar type spectral operators .

Thus for some constant K we have | S ( ) < K \ f | and to prove the final

**inequality**of the ...

Page 2399

By ( 44 ) and Hölder ' s

} " sko { f * 14 1 / 2 L112 | S | 2 . The

43 ) and ( 45 ) . Since the

By ( 44 ) and Hölder ' s

**inequality**we have ( 45 ) { { * ( ( ve ) – ( 0 + 3 ) ( x ) ] 2 due} " sko { f * 14 1 / 2 L112 | S | 2 . The

**inequality**( 42a ) follows immediately from (43 ) and ( 45 ) . Since the

**inequality**( 42b ) may be deduced in a precisely ...### What people are saying - Write a review

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### Contents

SPECTRAL OPERATORS XV Spectral Operators | 1924 |

Introduction | 1925 |

Terminology and Preliminary Notions | 1928 |

Copyright | |

32 other sections not shown

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