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Page 67
A closed linear manifold in a reflexive B - space is reflexive . Proof . Let Y be a
closed linear manifold in the reflexive space X . Let 6 : x * * y * be defined by the
equation $ ( w * ) y = x * y , y e Y . Clearly 1 $ ( w * ) ] = $ x * l , so that £ : X * → Y *
.
A closed linear manifold in a reflexive B - space is reflexive . Proof . Let Y be a
closed linear manifold in the reflexive space X . Let 6 : x * * y * be defined by the
equation $ ( w * ) y = x * y , y e Y . Clearly 1 $ ( w * ) ] = $ x * l , so that £ : X * → Y *
.
Page 72
19 If X is a reflexive B - space , and 3 is a closed subspace of X , show , using
Exercise 18 , that both 3 and X / 3 are reflexive . 20 If X is a B - space , with 3 CX ,
and both 3 and X / 3 are reflexive , then X is reflexive . ( Hint : Given any * * * e X *
* ...
19 If X is a reflexive B - space , and 3 is a closed subspace of X , show , using
Exercise 18 , that both 3 and X / 3 are reflexive . 20 If X is a B - space , with 3 CX ,
and both 3 and X / 3 are reflexive , then X is reflexive . ( Hint : Given any * * * e X *
* ...
Page 88
Reflexivity . The fact that the natural isomorphism of a B - space X into its second
conjugate is isometric was proved by Hahn [ 3 ; p . 219 ] who was ... He used the
term regular to describe what we , following Lorch [ 2 ] , have called reflexive .
Reflexivity . The fact that the natural isomorphism of a B - space X into its second
conjugate is isometric was proved by Hahn [ 3 ; p . 219 ] who was ... He used the
term regular to describe what we , following Lorch [ 2 ] , have called reflexive .
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Contents
Preliminary Concepts | 1 |
B Topological Preliminaries | 10 |
Algebraic Preliminaries | 34 |
Copyright | |
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algebra Amer analytic applied arbitrary assumed B-space Banach spaces bounded called clear closed compact operator complex condition Consequently constant contains continuous functions converges convex convex set Corollary countably additive defined DEFINITION denote dense determined differential dimensional disjoint domain element equation equivalent everywhere Exercise exists extension field finite follows formula function defined function f given Hence Hilbert space identity implies inequality integral interval Lebesgue Lemma limit linear functional linear operator linear space Math neighborhood norm operator operator topology problem projection PROOF properties proved range reflexive representation respect satisfies scalar seen semi-group separable sequence set function Show shown statement subset subspace sufficient Suppose Theorem theory topology u-measurable uniform uniformly unique unit sphere valued vector weak weakly compact zero