Linear Operators: General theory |
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Page 21
A set is said to be dense in a topological space X , if its closure is X . It is said to
be nowhere dense if its closure does not contain any open set . A space is
separable , if it contains a denumerable dense set . 12 THEOREM . If a
topological ...
A set is said to be dense in a topological space X , if its closure is X . It is said to
be nowhere dense if its closure does not contain any open set . A space is
separable , if it contains a denumerable dense set . 12 THEOREM . If a
topological ...
Page 450
If a convex subset of a separable B - space X has an interior point , it has a
unique tangent at each point of a dense subset of its boundary . PROOF . Let K
be the convex set . It will be shown that – 1 ( x , y ) = t ( x , - y ) , y e X , for æ in a
dense ...
If a convex subset of a separable B - space X has an interior point , it has a
unique tangent at each point of a dense subset of its boundary . PROOF . Let K
be the convex set . It will be shown that – 1 ( x , y ) = t ( x , - y ) , y e X , for æ in a
dense ...
Page 451
If we put Zn , i = V - Zn , i , ; , then Zn , is open in X , and Zn = n Zini We wish to
prove that Z = n Zn = nemocnice Zn , is dense in X . Suppose that Z is not dense
in X , and that p¢Z . Then some sphere S ( p , e ) does not intersect Z . If S = S ( p ,
ε ...
If we put Zn , i = V - Zn , i , ; , then Zn , is open in X , and Zn = n Zini We wish to
prove that Z = n Zn = nemocnice Zn , is dense in X . Suppose that Z is not dense
in X , and that p¢Z . Then some sphere S ( p , e ) does not intersect Z . If S = S ( p ,
ε ...
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Contents
Preliminary Concepts | 1 |
B Topological Preliminaries | 10 |
Algebraic Preliminaries | 34 |
Copyright | |
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Common terms and phrases
algebra Amer analytic applied arbitrary assumed B-space Banach spaces bounded called clear closed compact operator complex condition Consequently constant contains continuous functions converges convex convex set Corollary countably additive defined DEFINITION denote dense determined differential dimensional disjoint domain element equation equivalent everywhere Exercise exists extension field finite follows formula function defined function f given Hence Hilbert space identity implies inequality integral interval Lebesgue Lemma limit linear functional linear operator linear space Math neighborhood norm operator operator topology problem projection PROOF properties proved range reflexive representation respect satisfies scalar seen semi-group separable sequence set function Show shown statement subset subspace sufficient Suppose Theorem theory topology u-measurable uniform uniformly unique unit sphere valued vector weak weakly compact zero