Linear Operators, Part 1 |
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Page 8
Hence , by Theorem 7 , there is a maximal well - ordered subset E , of E. Now E ,
= E for if x is in E but not in E , the ordering S ... 2 If a family & of subsets of a set
has the property that A € E if and only if every finite subset of A belongs to E , then
...
Hence , by Theorem 7 , there is a maximal well - ordered subset E , of E. Now E ,
= E for if x is in E but not in E , the ordering S ... 2 If a family & of subsets of a set
has the property that A € E if and only if every finite subset of A belongs to E , then
...
Page 335
Then L is complete and every subset A of L has a least upper bound which is the
least upper bound of a countable subset of A. Proof . Let A be a subset of L which
has an upper bound and let A , be the collection of least upper bounds of all ...
Then L is complete and every subset A of L has a least upper bound which is the
least upper bound of a countable subset of A. Proof . Let A be a subset of L which
has an upper bound and let A , be the collection of least upper bounds of all ...
Page 440
totally ordered subfamily of A , the non - void set n A , is a closed extremal subset
of K which furnishes a lower bound for A 1. It follows by Zorn's lemma that A
contains a minimal element Ag . Suppose that A , contains two distinct points p
and q ...
totally ordered subfamily of A , the non - void set n A , is a closed extremal subset
of K which furnishes a lower bound for A 1. It follows by Zorn's lemma that A
contains a minimal element Ag . Suppose that A , contains two distinct points p
and q ...
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Contents
Preliminary Concepts | 1 |
The VitaliHahnSaks Theorem and Spaces of Measures | 7 |
B Topological Preliminaries | 10 |
Copyright | |
87 other sections not shown
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