Linear Operators, Part 1 |
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Page 262
Since the integral [ st ( s ) u ( ds ) satisfies the inequality 1st ( s ) p ( ds ) = sup \ t (
s ) 0 ( 11 , S ) , 8 it is clear that the integral is a continuous linear functional on C (
S ) . The following theorem is a converse to this statement . 2 THEOREM .
Since the integral [ st ( s ) u ( ds ) satisfies the inequality 1st ( s ) p ( ds ) = sup \ t (
s ) 0 ( 11 , S ) , 8 it is clear that the integral is a continuous linear functional on C (
S ) . The following theorem is a converse to this statement . 2 THEOREM .
Page 282
It is clear that T ( 8 ) CT ( d ) if € < d and that -te T ( E ) whenever te T ( € ) . The
function f is said to be almost periodic if it is continuous and if for every e > 0 there
is an L L ( 8 ) > 0 such that every interval in R of length L contains at least one ...
It is clear that T ( 8 ) CT ( d ) if € < d and that -te T ( E ) whenever te T ( € ) . The
function f is said to be almost periodic if it is continuous and if for every e > 0 there
is an L L ( 8 ) > 0 such that every interval in R of length L contains at least one ...
Page 292
Let E , be the family of all sets E in E for which lim un ( EF ) exists for each Fe E1 ,
and let E , be the family of all sets E in E , for which EF e E , for each Fe En . It is
clear that if F , and F , are elements of E3 , then F F2 € Eg . It is also clear that if F
...
Let E , be the family of all sets E in E for which lim un ( EF ) exists for each Fe E1 ,
and let E , be the family of all sets E in E , for which EF e E , for each Fe En . It is
clear that if F , and F , are elements of E3 , then F F2 € Eg . It is also clear that if F
...
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Contents
Preliminary Concepts | 1 |
The VitaliHahnSaks Theorem and Spaces of Measures | 7 |
B Topological Preliminaries | 10 |
Copyright | |
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