## Linear Operators: Spectral theory |

### From inside the book

Results 1-3 of 67

Page 1310

Then the boundary conditions are real , and there is exactly one

Then the boundary conditions are real , and there is exactly one

**solution**olt , 2 ) of ( 1-1 ) 9 = 0 square - integrable at a and satisfying the boundary conditions at a , and exactly one**solution**y ( t , 2 ) of ( 1-2 ) y = 0 square ...Page 1521

Putting y = 1 / 2 + i so that no = 1 + i , we see that the yo equation ( L - holf has one

Putting y = 1 / 2 + i so that no = 1 + i , we see that the yo equation ( L - holf has one

**solution**of the order of t - l - i as t → 00 and another which behaves like t ' as t → 00. The**solution**at ho = 1 - i is exactly similar .Page 1553

Suppose that q is bounded below on the interval ( 0 , 0 ) , and let | be a bounded

Suppose that q is bounded below on the interval ( 0 , 0 ) , and let | be a bounded

**solution**of the equation ( 1-1 ) ... ( b ) if all**solutions**of the equation ( 2-1 ) } = 0 are bounded , then 2 belongs to the essential spectrum of t .### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Contents

BAlgebras | 859 |

Bounded Normal Operators in Hilbert Space | 887 |

Miscellaneous Applications | 937 |

Copyright | |

13 other sections not shown

### Other editions - View all

### Common terms and phrases

additive Akad algebra Amer analytic assume Banach spaces basis belongs Borel boundary conditions boundary values bounded called clear closed closure coefficients compact complex Consequently constant contains continuous converges Corollary corresponding defined Definition denote dense determined domain eigenvalues element equal equation essential spectrum evident Exercise exists extension finite follows formal differential operator formula function given Hence Hilbert space identity independent indices inequality integral interval Lemma limit linear mapping Math matrix measure multiplicity Nauk neighborhood norm obtained partial positive preceding present problem projection proof properties prove range regular remark representation respectively restriction result Russian satisfies seen sequence singular solution spectral square-integrable statement subset subspace sufficiently Suppose symmetric Theorem theory topology transform unique vanishes vector zero