## Linear Operators, Part 2 |

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Page 884

The

The

**results**of Section 2 are due to Gelfand [ 1 ] . ... In their proof , they proved Lemma 3.5 by using a fairly deep**result**of Šilov that was not generally ...Page 1419

We will show that ( m ) 2 \ | ( mi + 1 ) 2 / ( mi + 2 ) 2 ... , which will clearly establish the desired

We will show that ( m ) 2 \ | ( mi + 1 ) 2 / ( mi + 2 ) 2 ... , which will clearly establish the desired

**result**. On the interval [ si + 1 , mi + 1 ] ...Page 1433

We shall not give the details of this

We shall not give the details of this

**result**here , but instead refer the reader to the excellent exposition of this point in Poole ( 1 ) and Coddington and ...### What people are saying - Write a review

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### Contents

BAlgebras | 859 |

Bounded Normal Operators in Hilbert Space | 887 |

Miscellaneous Applications | 937 |

Copyright | |

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additive Akad algebra Amer analytic assume Banach spaces basis belongs Borel boundary conditions boundary values bounded called clear closed closure coefficients compact complex Consequently constant contains continuous converges Corollary corresponding defined Definition denote dense determined domain eigenvalues element equal equation essential spectrum evident Exercise exists extension finite follows formal differential operator formula function function f given Hence Hilbert space identity independent indices inequality integral interval Lemma limit linear mapping Math matrix measure multiplicity neighborhood norm obtained partial positive preceding present problem projection proof properties prove range regular remark representation respectively restriction result Russian satisfies seen sequence singular solution spectral square-integrable statement subset subspace sufficiently Suppose symmetric Theorem theory topology transform unique vanishes vector zero