## Linear Operators: Spectral theory |

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Page 1272

If T is a symmetric operator with dense domain , then it has proper symmetric extensions provided both of its deficiency

If T is a symmetric operator with dense domain , then it has proper symmetric extensions provided both of its deficiency

**indices**are different from zero . A maximal symmetric operator is one which has no proper symmetric ...Page 1398

Let t be a formally self adjoint formal differential operator defined on an interval I. If the minimum of the deficiency

Let t be a formally self adjoint formal differential operator defined on an interval I. If the minimum of the deficiency

**indices**of To ( t ) is k , then for 1 $ 0 , ( T ) the equation to = lo has at least k linearly independent ...Page 1610

( 16 ) Suppose that ( a , b ) [ 0 , 0 ) , that the deficiency

( 16 ) Suppose that ( a , b ) [ 0 , 0 ) , that the deficiency

**indices**of t are equal and that there exists a sequence { { n } of square - integrable functions such that in vanishes in the interval [ 0 , n ] , lind = 1 , and | ( 2 - ) in ...### What people are saying - Write a review

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### Contents

BAlgebras | 859 |

Bounded Normal Operators in Hilbert Space | 887 |

Miscellaneous Applications | 937 |

Copyright | |

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additive Akad algebra Amer analytic assume Banach spaces basis belongs Borel boundary conditions boundary values bounded called clear closed closure coefficients compact complex Consequently constant contains continuous converges Corollary corresponding defined Definition denote dense determined domain eigenvalues element equal equation essential spectrum evident Exercise exists extension finite follows formal differential operator formula function given Hence Hilbert space identity independent indices inequality integral interval Lemma limit linear mapping Math matrix measure multiplicity Nauk neighborhood norm obtained partial positive preceding present problem projection proof properties prove range regular remark representation respectively restriction result Russian satisfies seen sequence singular solution spectral square-integrable statement subset subspace sufficiently Suppose symmetric Theorem theory topology transform unique vanishes vector zero