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Page 1452
It is evident from Definition XII . 5 . 1 that if T , is bounded below , T , must also be
bounded below . Conversely , let T , be bounded below . Suppose that the lemma
is false , so that T , is not bounded below . We shall show by induction that for ...
It is evident from Definition XII . 5 . 1 that if T , is bounded below , T , must also be
bounded below . Conversely , let T , be bounded below . Suppose that the lemma
is false , so that T , is not bounded below . We shall show by induction that for ...
Page 1631
It is evident that T is linear , and equally evident that T is closed . Hence , by the
closed graph theorem ( II . 2 . 4 ) , T is continuous . Hence given any e > 0 and
any k , there is an integer l and a d > 0 such that ulk , T [ go , . . . 8m - 1 ] ) <
provided ...
It is evident that T is linear , and equally evident that T is closed . Hence , by the
closed graph theorem ( II . 2 . 4 ) , T is continuous . Hence given any e > 0 and
any k , there is an integer l and a d > 0 such that ulk , T [ go , . . . 8m - 1 ] ) <
provided ...
Page 1662
However , an evident consequence of Lemma 12 , as generalized to D . ( I ) ,
which will be of importance to us in subsequent discussions , is stated in the
following lemma . 33 LEMMA . Let I be an open subset of the interior of C , and let
F be in ...
However , an evident consequence of Lemma 12 , as generalized to D . ( I ) ,
which will be of importance to us in subsequent discussions , is stated in the
following lemma . 33 LEMMA . Let I be an open subset of the interior of C , and let
F be in ...
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Contents
IX | 859 |
Eigenvalues and Eigenvectors | 903 |
Spectral Representation | 911 |
Copyright | |
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additive Akad algebra Amer analytic assume Banach spaces basis belongs Borel boundary conditions boundary values bounded called clear closed closure coefficients compact complex Consequently constant contains continuous converges Corollary corresponding defined Definition denote dense determined domain eigenvalues element equal equation essential spectrum evident Exercise exists extension finite follows formal differential operator formula function function f given Hence Hilbert space identity independent indices inequality integral interval Lemma limit linear mapping Math matrix measure multiplicity neighborhood norm obtained partial positive preceding present problem projection proof properties prove range regular remark representation respectively restriction result Russian satisfies seen sequence shown singular solution spectral square-integrable statement subset subspace sufficiently Suppose symmetric Theorem theory topology transform unique vanishes vector zero