## Linear Operators, Part 2 |

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Page 876

Then ( y + Nie ) ( 2 ) y ( 2 ) + Ni = i ( 1 + N ) , and

Then ( y + Nie ) ( 2 ) y ( 2 ) + Ni = i ( 1 + N ) , and

**hence**11+ N = ly + Niel .**Hence**( 1 + N ) 2 = \ y + Niel2 = [ ( y + Nie ) ( y + Nie ) * 1 = | ( y + ...Page 1027

Ex .

Ex .

**Hence**a belongs to the spectrum of ET . Conversely , suppose that a non - zero scalar belongs to the spectrum of ET . Then , for some non - zero a in ...Page 1227

**Hence**T * x = ix , or x e Dt .**Hence**Dt is closed . Similarly , D is closed . Since D4 and D are clearly linear subspaces of D ( T * ) , it remains to show ...### What people are saying - Write a review

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### Contents

BAlgebras | 859 |

Bounded Normal Operators in Hilbert Space | 887 |

Miscellaneous Applications | 937 |

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