Linear Operators: Spectral theory |
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Page 876
Then ( y + Nie ) ( 2 ) = y ( 2 ) + Ni = i ( i + N ) , and hence 1 + N < ly + Niel . Hence N ( 1 + N ) 2 = \ y + Nie | 2 = | ( y + Nie ) ( y + Nie ) * 1 = | ( y + Nie ) ( y - Nie ) \ y2 + Nel = 1741 + N2 . Since this inequality must hold ...
Then ( y + Nie ) ( 2 ) = y ( 2 ) + Ni = i ( i + N ) , and hence 1 + N < ly + Niel . Hence N ( 1 + N ) 2 = \ y + Nie | 2 = | ( y + Nie ) ( y + Nie ) * 1 = | ( y + Nie ) ( y - Nie ) \ y2 + Nel = 1741 + N2 . Since this inequality must hold ...
Page 1027
Hence a belongs to the spectrum of ET . Conversely , suppose that a non - zero scalar , belongs to the spectrum of ET . Then , for some non - zero x in EH , we have ETx = 2x . Then Tx = 2x + y , where y belongs to the , subspace ( I - E ) ...
Hence a belongs to the spectrum of ET . Conversely , suppose that a non - zero scalar , belongs to the spectrum of ET . Then , for some non - zero x in EH , we have ETx = 2x . Then Tx = 2x + y , where y belongs to the , subspace ( I - E ) ...
Page 1227
Hence T * x = ir , or xe Dr. Hence D. is closed . Similarly , = Dt D is closed . Since D4 and D_ are clearly linear subspaces of D ( T * ) , it remains to show that the spaces D ( T ) , D. , and D_ are mutually orthogonal , and that ...
Hence T * x = ir , or xe Dr. Hence D. is closed . Similarly , = Dt D is closed . Since D4 and D_ are clearly linear subspaces of D ( T * ) , it remains to show that the spaces D ( T ) , D. , and D_ are mutually orthogonal , and that ...
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Contents
BAlgebras | 859 |
Bounded Normal Operators in Hilbert Space | 887 |
Miscellaneous Applications | 937 |
Copyright | |
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